Part a
|
Gender |
Mode of Transport |
||
|
Driver |
Passenger |
Other |
|
|
Female |
28 |
61 |
39 |
|
Male |
52 |
62 |
29 |
|
Gender |
Mode of Transport |
Total |
||
|
Driver |
Passenger |
Other |
||
|
Female |
28 |
61 |
39 |
128 |
|
21.9% |
47.7% |
30.5% |
100% |
|
|
Male |
52 |
62 |
29 |
143 |
|
36.4% |
43.4% |
20.3% |
100% |
The row percentage is used to review the relationship between gender and mode of transport. It is seen that the passenger mode of transport has been the most frequently used by both females (47.7%) and males (43.4%).
|
Statistics |
Not-licenced |
Learners permit |
Licenced |
|
Mean |
6.550725 |
6.293333 |
8.370079 |
|
Standard Deviation |
2.179694 |
2.252766 |
2.107444 |
|
Minimum |
3 |
2 |
3 |
|
1st Quartile |
5 |
4 |
7 |
|
Median |
6 |
6 |
9 |
|
3rd Quartile |
8 |
8 |
10 |
|
Maximum |
11 |
12 |
13 |
|
Range |
8 |
10 |
10 |
|
IQR |
3 |
4 |
3 |
|
Skewness |
0.135572 |
0.3590054 |
-0.2056677 |
The above table represents the descriptive statistics for the number of activities and driver’s licence Mean and median values represent the centre of the distribution. The spread of the distribution is represented by both range and IQR. The shape of the distribution is provided by skewness.
From the graph in “part a” and table in “part b” it can be inferred that the average number of activities attended by licenced drivers is more than Not-licenced and Learners permit holders. In addition, the median number activities attended by licenced drivers is also more than Not-licensed and Learners permit holders. The range of Licenced drivers and learners permit is more than not-licenced drivers. Moreover, while the activities attended by Licenced drivers is right skewed, the number of activities attended by Not-licenced and Learners permit is left skewed.
From the above plot it can be inferred that with decrease in number of sed there is an increase in the number of activities.
From the table it is found that 7 out of 8 persons are more than 18 years of age.
Thus, if a person is selected at random then the probability that he would be more than 18 years of age = 1/8 = 0.875
The group
|
Gender |
Area of Study |
Total |
||
|
Accounting |
Nursing |
Psychology |
||
|
Female |
0 |
2 |
2 |
4 |
|
Male |
1 |
1 |
2 |
4 |
|
Total |
1 |
3 |
4 |
8 |
From the above table it is seen that the total number of people = 8
Number of females studying psychology = 2
Thus, the probability that a person chosen randomly would be female and studying psychology =2/8 = 0.25
Number of Students 21 years or more = 4
For students 21 years and more
|
Gender |
Area of Study |
Total |
||
|
Accounting |
Nursing |
Psychology |
||
|
Female |
0 |
2 |
1 |
3 |
|
Male |
0 |
0 |
1 |
1 |
|
Total |
0 |
2 |
2 |
4 |
From the above table it is seen that the total number of females = 3
Number of females studying Nursing = 2
Thus, the probability that a female chosen randomly would be 21 years or more and studying Nursing =2/3 =0.67
The probability is given as
Thus, the random sample of 250 adults will contain 25 or fewer people with blood group B = 0.5
Let the number of people with type B Blood be x
Each, sample contains 250 people.
Thus the proportion of people
The proportion of people with blood type B = 0.1
Thus, there are fewer than 26 people with blood type B in a sample
Thus, the mean number of people per sample with blood type B = 26*0.1 = 2.6
z-score = 1
mean number of hours of sleep = 8.2
standard deviation of hours of sleep = 0.6
Thus, 8.8 hours of sleep corresponds to z-score of 1
The probability that the persons sleeps between 8.0 and 7.5 hours 0.2477688
The probability is given as P(7.5<x<8.0) when the sample size is 16
The standard error
Thus the probability that the sample mean would lie between 7.5 and 8.0 hours = 0.0912
The probability = 0.0912
The sample size = 16
Thus the number in the groups = 16*0.0912 = 1.4592 ≈1
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