Online Plagiarism And Referencing Quiz For ITC544 Students

Question 1:

a) Given (152) _x= (6A) ₁₆   

• X² + (5 * X¹) + (2 * X⁰) = (6 * 16¹) + (10 * 16⁰)
• X² + 5X + 2 = 106
• X² + 5X – 104 = 0
• X² + 13X – 8X – 104 = 0
• X(X + 13) – 8(X + 13) = 0
• (X – 8) (X + 13) = 0
• X = 8 and X = -13

Therefore,  X is 8.

(152)₈= (6A) ₁₆ 

1. b) i) BED = (B * 16²) + (E * 16¹) + (D * 16⁰)

      = 2816 + 224 + 13

      = (3053)₁₀

(3053)₁₀ = 

BED₁₆ = (11012002)₃

1. ii) (321)₇ = (3 * 7²) + (2 * 7¹) + (1 * 7⁰)

= (162)₁₀

Again, (162)₁₀ =

(162)₁₀ = (10100010)₂

iii) Conversion

Therefore, (1235)₁₀ = (2323)₈

1. iv) As per given question 21₈ = (2 * 8¹) + (1 * 8⁰). (2 * 8^-1) + (1 * 7=8^-2)

      = 17 + 0.25 + 0.015625

      = 17.265625

(21.21)₈ =  17.265625

1. c) i) Negative smallest number for one’s compliment = 100

            Positive largest number for one’s compliment = 100

1. ii) Negative smallest number for two’s compliment = 101

            Positive largest number for two’s compliment = 011

iii) Negative smallest number for signed magnitude = 111

            Positive largest number for signed magnitude = 011

Question 2:

1. a) After generating the output from L.H.S.

After generating the output from R.H.S.

So, L.H.S. is same as R.H.S.

) The two not gate and the and can be minimized as

Can be represented by

Therefore, finalized circuit is

1. c) X’ + Y’ + XYZ’

= X’ + Y’ + (X’ + Y’ + Z)’ [From De-Morgan’s Law]

= (XY (X’ + Y’ + Z))’ [From De-Morgan’s Law]

= (XX’Y + XYY’ + XYZ)

= (0 + 0 + XYZ)

= (XYZ)’

= X’ + Y’ + Z’ [From De-Morgan’s Law]

= X’ + Y’ + XYZ’ = X’ + Y’ + Z’ [HENCE, PROVED]

Order an Essay Now & Get These Features For Free:

Turnitin Report

Formatting

Title Page

Citation

Outline

Place an Order